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sin三分之十七π

sin三分之四π=sin(π/3+π)=-sinπ/3=-根号3/2 满意请及时采纳

=sin(兀+2/3兀)=sin2/3兀=sin120度=√3/2

cos(-9/4π)=cos(-9/4π+2π)=cos(-π/4)=cosπ/4=√2/2 tan11/6π=tan(11/6π-2π)=tan(-π/6)=tanπ/6=√3/3 sin600°=sin(600°-720°)=sin(-120°)=-√3/2

sin-17π/3=sin(-6π+π/3)=sin(π/3)=√3/2

答案:(根号3)/2,sin-17π/3=sinπ/3=(根号3)/2

sin(-17π/3)=sin(-6π+π/3)=sin(π/3)=(√3)/2(sin是周期函数,sin(x+2kπ)=sin(x))cos(-17π/3)=cos(-6π+π/3)=cos(π/3)=1/2(cos也是周期函数,cos(x+2kπ)=cos(x))tan(-17π/3)=sin(-17π/3)/cos(-17π/3)=√3

它们是周期函数啊 Sin17/3派就是Sin120度啊 后面的是一样这么算 看它们的周期

解:sin(5/3)π=sin(-5/3+2)π=sin1/3π=二分之根号三 cos(17/4π)=cos(-17/4+2)π=cos(-1/4)π=cos(1/4)π=二分之根号二

解:(1)因为-17π/3=(-18π/3)+π/3=-6π+π/3 所以 sin(-17π/3)=sin(-6π+π/3)=-sin(6π-π/3)=-sin(-π/3)=sin(π/3)=2分之根号3 cos(-17π/3)=cos(-6π+π/3)=cos(6π-π/3)=cos(π/3)=1/2 tan(-17π/3)=根号3

tan3分之11派=tan(4π-π/3)=-tan(π/3)=-√3;sin3分之17派=sin(6π-π/3)=-sin(π/3)=-√3/2cos(-6分之7派)=cos(7π/6)=cos(π+π/6)=-cos(π/6)=-√3/2tan(-4分之7派)=tan(-2π+π/4)=tan(π/4)=1sin900°=sin(720°+180°)=sin180°=0

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